搞明白了怎么显示了，先写个显示的demo显示数字0，为了便于仿真，不停输出，实际使用的时候，是可以锁在的，不改变数字时，不用写入，然后再用proteus仿真一下，因为proteus里没有SAA1060这个元件，要不可直接看数码管显示，现在只能看虚拟仪器里的时序了，代码附后，代码写得效率可能不是很好，但看仿真的结果应该是没有问题。
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demo 的代码在这里0 K% m" J, ^+ p- B% w% o& `' g+ W- j
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#include "reg52.h" //此文件中定义了单片机的一些特殊功能寄存器* n* S7 q) N, Z3 J3 D, Q; U6 [& @
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sbit yData = P2^0;6 ^5 r y+ [3 c# ~9 l- b% W
sbit yDLEN = P2^2;4 }+ ^/ F; L- {
sbit yCLK = P2^1;
4 `3 D, D+ k7 X, C+ L( Rconst int dailyCount = 200;/ d) y5 u: J, z- X. Y5 D. S
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void delay(unsigned int i), j: n [2 k9 S; J$ a; O
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while(i--); 1 m* O& a. D4 z1 f; w0 l9 S7 |
}
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void disp(unsigned int num )
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8 b( [% }4 m- y& q% t# T7 p unsigned char i ;
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! L& z' Y$ l- K: j1 b unsigned char dispA[20];
% I0 P) J4 G! g. W& Q- c7 b* e unsigned char dispB[20];
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unsigned char num1;' B- r5 g5 W+ t/ p) n' z
unsigned char num2; & D( c4 A6 g; i6 \+ C% G
unsigned char num3;
, \ _8 ^+ p" y unsigned char num4;
, W& q" n) A: m" ?; Z unsigned char segR[10] ; //右
1 ^3 n$ @" M7 q2 h$ A unsigned char segL[10]; //左
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9 n0 l/ F. V" y2 o //左 + J$ `9 R! M1 I8 s0 k) g
segL[0] = 0x12;
+ l" s2 m& v p segL[1] = 0xFA;
( N" l6 ^7 a% T1 ?% J segL[2] = 0x0E;
# ]! O4 N, T* A5 c8 O5 G segL[3] = 0x2A;2 j% w% [* w( f, E V$ F8 |( v
segL[4] = 0xE2;6 W# n3 f8 ]! p7 ~, ~0 g/ S4 R
segL[5] = 0x63;
$ C+ G/ x# Z. g* u) D3 ? segL[6] = 0x2A;! R9 K2 @/ O6 r: S+ u" U. b
segL[7] = 0x7A;
" M L! A3 ?) r( ^( s0 A4 u0 ~5 } segL[8] = 0x02;. y; r+ g R! t5 _5 v. |9 l$ n( s8 j
segL[9] = 0x22;
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//右
1 z7 ?/ \; T2 @. `; d segR[0] = 0x88;0 c) f5 c( i2 ?3 r
segR[1] = 0xEB;& a6 @+ k$ i6 G+ ], p$ M
segR[2] = 0x85;9 y E5 _( J" g/ \* \
segR[3] = 0x83;
% ]" @9 P# F. j' j& ]' @ segR[4] = 0xE2;
2 Y& q3 P4 a# j" ^ segR[5] = 0x92;- T& H0 x3 Y: N4 v
segR[6] = 0x90;
) [1 v% V$ D9 S5 y( S6 D6 @% d segR[7] = 0xCB;
) K! T9 m# e+ D8 ?8 [9 [5 c$ r0 d8 ] segR[8] = 0x80;7 }% p" t# n/ U7 r
segR[9] = 0x82;& ~: j$ b: H$ c; p
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- N% t @9 ]& c6 e$ H num1=num /1000;3 `, o- x$ L* t; _
num2=(num /100)%10;;
3 H3 m( y9 d; I5 r num3=(num /10)%100;;;) M8 r3 ]6 l- c$ E" |5 Z2 C
num4=num%10;7 W3 p% O* N, ?4 q! R8 f
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dispA[0] = 0;! s: y1 p$ k; D8 w$ ?9 x7 d0 D
dispB[0] = 0;
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3 R9 |# Q% v) k' \/ e# ] for (i=0;i<8;i++)
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dispA[i+1] = (segR[num2]>>i)&0x01;* L- ^+ A/ T& y: w8 E+ p
dispB[i+1] = (segR[num1]>>i)&0x01; / Z$ P# p- ^- ?
2 ~* C, c9 V, _: Z2 a% I# }1 f dispA[i+9] = (segL[num4]>>i)&0x01;
: b# t# `& R: L1 u) y1 U dispB[i+9] = (segL[num3]>>i)&0x01;/ B. g8 `1 b' v6 |7 |
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. s% M5 e% d8 |. } dispA[17] = 1;* T4 ]3 m* }( J2 p' Y
dispB[17] = 0;( {8 k. Z( d* A2 d( v
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dispA[18] = 0;
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dispA[19] = 0;+ u9 N$ j# {+ \, n e. h
dispB[19] = 0;! [% j0 Z) l% q8 u
( X6 F7 E0 s/ m, W yCLK = 1;0 c! c2 h- C8 n- l+ E1 n: b
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0 P$ I5 Q( }# w% h& L0 ~ for (i = 0;i<20;i++)6 @5 k) q( @ M4 w
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yCLK = 1;' ^1 _8 Y2 f5 ?! S
yData = dispA;
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if(i>17)6 n2 ?4 Q& n1 L0 C
{yDLEN=0;}
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1 C( M/ D3 f A5 U! a {yDLEN=1;}$ }% ^& l9 m5 N9 B% w& S
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delay(dailyCount);
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delay(dailyCount);. Z7 r/ B# u) p; D! b# o) S
}
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0 \' x' \5 p7 m% |( o- ~ yCLK=0;
' h( h y/ Y6 V yData=0;- s+ V7 t; @4 v8 u8 t4 {! j2 E6 u
yDLEN=0; A$ D2 }' S) x) v: L, U1 b2 N
delay(dailyCount*10);
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' A2 C+ a# ~- C5 w" ] yCLK = 1;
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delay(dailyCount/10);% h1 k2 A8 {' D! O( X2 r4 a
if(i>17)
. u7 T6 E( P& X* b8 U$ e {yDLEN=0;}3 a4 W2 t7 _( k" X2 a, m: i; J
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{yDLEN=1;}8 Z* C* y! S: ]7 n* p+ x; K/ y
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delay(dailyCount);! a+ C! O/ J9 t9 c, i
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delay(dailyCount*10);
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void main()
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, `+ \# Q- g \! w. @ while(1)
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8 O- i9 t! D# h2 N* M$ U/ H4 m delay(4000);
; ~$ q5 ]+ }$ Y% V" s disp(0);
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发表于 2018-10-20 15:24:50
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